1.

A Steel rod of length 25 cm has a cross - sectional area of 0.8cm^(2). The force required to stretch this rod by the same amount as the expansion produced by heating it through 10^(@)C is (coefficient of linear expansion of steel is 10^(-5)//^(@)C and Young's modulus of steel is 2xx10^(10)N//m^(2)).................... .

Answer»

(a) 40 N
(b) 80 N
(c) 120 N
(d) 160 N

Solution :The REQUIRED force is GIVEN by
`F=YA ALPHA Deltat=2xx10^(10)xx0.8xx10^(-4)xx10^(-5)xx10`
`F=160N`


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