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| 1. |
A steel wire of length 1.5m and diameter 0.25cm is loaded with a force of 98N The increase in length of the wire is 1.5xx10^-4m.Calculate the tensile stress and the fractional change in length of the wire. |
| Answer» SOLUTION :L=1.5m, r=d/2 =`0.125xx10^-2 m,F=98N, deltaL=1.5xx10^-4m`STRESS `=F/A = F/pi r^2 =98//3.14xx(0.125xx10^-2)^2=1.99xx10^7Nm^-2 `FRACTIONAL CHANGE in LENGTH, `deltaL//L= 1.5xx10^-4//1.5 =10^-4` | |