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A steel wire of length 2.5 m and area of cross section `1.25 mm^(2)`, when it is stretched by a force of 40 N and Y for steel is `2xx10^(11)N//m^(2)`. The extension produced in a steel wire isA. 0.4 mmB. 0.4 cmC. 4 mmD. 4 cm |
Answer» Correct Answer - A `y=(FL)/(Al)` `therefore l=(40xx2.5)/(2xx10^(11)xx1.25xx10^(-6))=0.4 mm. ` |
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