A steel wire of length 2 m and cross sectional area 2 mm^2is fixed at one end and stretched by suspending a block of mass 2 kg on the surface of the moon. If the Young's modulus of steel is 2 xx 10^11 N m^(-2)find the increase in the length of the steel wire. (g on the moon = 1/6 of the g on the earth)

A steel wire of length 2 m and cross sectional area 2 mm^2is fixed at

1.	A steel wire of length 2 m and cross sectional area 2 mm^2is fixed at one end and stretched by suspending a block of mass 2 kg on the surface of the moon. If the Young's modulus of steel is 2 xx 10^11 N m^(-2)find the increase in the length of the steel wire. (g on the moon = 1/6 of the g on the earth)
Answer» Solution :`L= 2 m, A= 2 mm^2 = 2 XX 10^(-6) m^2`, M = 2 kg: g on the MOON =`g/6 = (9.8)/(6) ms^(-2)` `Y = 2 xx 10^11 (N)/(m^2) , e = ?` The increase in length ` e = (FL)/(AY) = (MgL)/(AY) = (2 xx 9.8 xx 2)/(6 xx 2 xx 10^(-6) xx 2 xx 10^11)` ` = 1.633 xx 10^(-5) m`