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A stell wire of 1m long `1mm^(2)` cross section area is hang from rigid end. The length of 1kg is hung from it then change in length will be (given `Y = 2 xx 10^(11) N//m^(2)`)A. 0.5 mmB. 0.25 mmC. 0.05 mmD. 5 mm |
Answer» Correct Answer - C |
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