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A stone dropped from a building takes 4 seconds to reach the ground. The height of the building is |
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Answer» tion:initial VELOCITY = 0time TAKEN = 4sacceleration = g = 9.8m/s^2using 2ND equation of motion s= ut +(1/2)at^2= (0)(4) +(1/2)(9.8)(4)(4)= 78.4So, distance COVERED by that stone was 78.4m |
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