InterviewSolution
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InterviewSolution
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A stone falls freely under gravity. It covered distances `h_1, h_2` and `h_3` in the first `5` seconds. The next `5` seconds and the next `5` seconds respectively. The relation between `h_1, h_2` and `h_3` is :A. ` h_1 = h_2 =h_23`B. ` h_1 =2 h_2 =3 h_3`C. ` h_1 = h_2/3 = h_3/5`D. ` h_2 = 3 h_1 `amd ` h_3 = 3 h_2` |
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Answer» Correct Answer - A Here, ` h_1 = 1/2 g (5)^2 = (250/2 g ,` ` (h-1 + h_2 ) = 1/2 g ( 5 +5 )^2 = 50 g` `( h_1 + h_2 = h_3 ) =1/2 g ( 5 + 5 =5)^2 = (225)/2 g` Now ` h_2 = (h_1 = h_2) - h_1 = 50 g- (25)/2 g` ` = ( 75)/2 g= 3 h_1` or ` h_1 = _2/3 ` And ` h_3 = ( h_1 +h_2 + h_3 ) - ( h_1 + h_2)` ` = ( 225)/2 g - 50 = (125)/5 g = 5 h_1` or ` h_1 = h_3 /5` Chocie (c ) is correct . |
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