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A stone is allowed to fall from the top of a tower 300m height and at the same time another stone is projected vertically up from the ground with a velocity 100ms^(-1). Find when and where the two stones meet? |
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Answer» Solution :Suppose the two stones meet at a HEIGHT x from ground after t SECONDS. `x=100t-(1)/(2)g t^(2)…..(1)` `300-x=0+(1)/(2)g t^(2)…..(2)` Solve 1, 2 `t=3` SEC, `x=255.9m` |
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