A stone is allowed to fall from the top of a tower 300m height and at the same time another stone is projected vertically up from the ground with a velocity 100ms^(-1). Find when and where the two stones meet?

A stone is allowed to fall from the top of a tower 300m height and at

1.	A stone is allowed to fall from the top of a tower 300m height and at the same time another stone is projected vertically up from the ground with a velocity 100ms^(-1). Find when and where the two stones meet?
Answer» <html><body><p></p>Solution :Suppose the two stones meet at a <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> x from ground after t <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a>. <br/> `x=100t-(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)g t^(2)…..(1)` <br/> `300-x=0+(1)/(2)g t^(2)…..(2)` <br/> Solve 1, 2 <br/> `t=3` <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>, `x=255.9m`</body></html>