Saved Bookmarks
| 1. |
A stone is dropped from 4.9 m above water level. It entered with velocity v and then continue at constant velocity v. It took 4 seconds from throw to reach ground. Find depth of water. (a) 20.4 m (b) 29.4 m (c) 2.94 m(d) 19.4 m |
|
Answer» Correct option is (b) 29.4 m Velocity after falling through a height of 4.9 m v2 - u2 = 2as v2 - 0 = 2(9.8) (4.9) v = 9.8 m/s Time taken to fall by 4.9 m 9.8 = 0 + 9.8t ⇒ t = 1 sec Rest of 3 sec it went inside water with constant speed 9.8 m/s ∴ Depth of water 9.8 x 3 = 29.4 cm |
|