A stone is dropped into water from a bridge 44.1 m above the water. Another stne is thrown vertically downward 1s later. Both strike the water simultaneously. What was the initial speed of the second stone?

A stone is dropped into water from a bridge 44.1 m above the water. An

1.	A stone is dropped into water from a bridge 44.1 m above the water. Another stne is thrown vertically downward 1s later. Both strike the water simultaneously. What was the initial speed of the second stone?
Answer» Solution :`t=SQRT((2 xx 44.1)/(9.8))s =sqrt(9s)=3S` `44.1=v xx 2+1/2 xx 9.8 xx 2 xx 2` `or 2v=44.1 -4.9 xx4=24.5 or` `v=(24.5)/(2) MS^(-1) =12.25ms^(-1)`