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A stone is dropped is dropped from the top of a tower 500 m high into a pond of water at the base of the tower . when is the Splash heard at the top ? Given,g= 10 m s‐² and speed of sound = 340 m s‐²...?????! |
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Answer» Height of the tower, s = 500 m VELOCITY of SOUND, v = 340 m sˆ’1 Acceleration due to gravity, G = 10 m sˆ’2 Initial velocity of the stone, u = 0 (since the stone is initially at rest) Time taken by the stone to fall to the base of the tower, t1 According to the second equation of motion: S = ut1 + 1/2gt12 500 = 0 x t1 + 1/2 x 10 x t12 t12 = 100 t1 = 10s Now, time taken by the sound to reach the top from the base of the tower, t2= 500/340 = 1.47 s Therefore, the splash is heard at the top after time, t Where, t= t1 + t2 = 10 + 1.47 = 11.47 s. |
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