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A stone is projected from level ground at t=0 sec such that its horizontal and vertical components of initial velocity are 10(m)/(s) and 20(m)/(s) respectively. Then the instant of time at which tangential and normal components of acceleration of stone are same is: (neglect air resistance)g=10(m)/(s^2). |
| Answer» Solution :Suppose a small ball ROLLS down ALONG a spiral with a CONSTANT SPEED it has both centripetal acceleration and tangential acceleration. | |