1.

A stone is released from the top of a tower of height 19.6m . calculate it's final velocity​

Answer»

U= 0
a = 9.8 m/sec SQUARE
s = 19.6 m

USING THIRD EQUATION OF MOTION
v square = u square + 2as

v square = 0 + 2 × 9.8 × 19.6
v square = 384.16
v = √384.16
v = 19.6 m/sec

ANSWER = 19.6 m/sec

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