A stone is thrown upwards with a speed y from the top of a tower. It reaches the ground with a velocity 3v. What is the height of the tower?

A stone is thrown upwards with a speed y from the top of a tower. It r

1.	A stone is thrown upwards with a speed y from the top of a tower. It reaches the ground with a velocity 3v. What is the height of the tower?
Answer» <html><body><p></p>Solution :From equation of motion <br/>v.`= u + at `….(1) <br/> `h = ut + 1/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> at^2` <br/> ` v.= av, u = v , a = + g` <br/>using <a href="https://interviewquestions.tuteehub.com/tag/eqn-973463" style="font-weight:bold;" target="_blank" title="Click to know more about EQN">EQN</a> (1) <br/> <a href="https://interviewquestions.tuteehub.com/tag/3v-310794" style="font-weight:bold;" target="_blank" title="Click to know more about 3V">3V</a> = v + gt `rArr` 3v - v = gt <br/> ` t=(2v)/(g)` <br/> substituting.t. <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> in eqn (2) <br/> `h = v ( (2v)/(g) ) + 1/2 g ( (2v)/(g) )^2 = (2v^2)/(g) + 1/2 g ( (2v)/(g) )^2` <br/> ` h = (2v^2)/(g) + (2v^2)/(g)` <br/>` = (4v^2)/(g) "" g = <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ms^(-2)` <br/> ` = (4v^2)/(10) , h = (2v^2)/(5)`</body></html>