1.

A stone is thrown upwards with initial velocity 'u' from top of a tower and it reaches to ground with velocity '3u' then height of the tower is ......

Answer»

`(3u ^(2))/(g) `
`(4U ^(2))/(g)`
`(6u^(2))/(g)`
`(9u^(2))/(g)`

Solution :`(3u) ^(2) -U^(2) =2gh`
`(because v = 3u, u=u, a = g and x=h)`
`THEREFORE 9u^(2) -u^(2) =2gh`
`therefore h = (8u^(2))4u^(2))/(g)`


Discussion

No Comment Found