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A stone is thrown upwards with initial velocity 'u' from top of a tower and it reaches to ground with velocity '3u' then height of the tower is ...... |
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Answer» `(3u ^(2))/(g) ` `(because v = 3u, u=u, a = g and x=h)` `THEREFORE 9u^(2) -u^(2) =2gh` `therefore h = (8u^(2))4u^(2))/(g)` |
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