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A stone is thrown vertically with a velocity of 5m/s. find time required to go up and as well as come down upto a point at which it is thrown upward |
| Answer» TION:GIVEN, initial velocity, u=5ms−1Final velocity, v=0Since, u is upward & a is downward, it is a retarded motion. ∴a=−10ms−2Height attained by stone, s=?TIME take to attain height, t=?(i) Using the RELATION, v2−u2=2as, we haves=v2−u2/2a=(0)2−(5)2/2×(−10)=1.25m(ii) Using the relation, v=u+at0=5+(−10)t ort=5/10=0.5s | |