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A stone is thrown with a velocity `v` at an angle `theta` with the horizontal.Its speed when it makes an angle `beta` with the horizontal isA. `v cos theta`B. `v/(cos beta)`C. `v cos theta cos beta`D. `(v cos theta)/(cos beta)` |
Answer» Correct Answer - D `V cos theta=V^(1) cos beta , :.V^(1)=(V cos theta)/(cos beta)` |
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