A stone is tied at end of string and whirled in horizontal plane with circular path of radius 20 cm. If its acceleration is 980 cms^(-2), then what will be its angular speed ?

A stone is tied at end of string and whirled in horizontal plane with

1.	A stone is tied at end of string and whirled in horizontal plane with circular path of radius 20 cm. If its acceleration is 980 cms^(-2), then what will be its angular speed ?
Answer» Solution :Centripetalacceleration `a_(c )= (V^(2))/( r )` `=r epsilon^(2) ` `epsilon = sqrt((a)/(r )) = sqrt((960)/( 20))` `epsilon = sqrt(49) =7 (rad)/( s )`