1.

A stone of 0.36 m^(2) cross -sectional area and 0.1 m thickness has its lower surface in contact with water at 100^(@)C and upper surface in contact with ice at 0^(@)C. If 4.8 kg ice melting in 1 hour, then what is the thermal conductivity of stone ? Latent heat of fusion of ice is 3.36xx10^(5)" J/kg".

Answer»

`1.24" J/ms "^(@)C`
`1.29" J/ms "^(@)C`
`2.05" J/ms "^(@)C`
`1.02" J/ms "^(@)C`

Solution :`Q=KA((T_(1)-T_(2))/(L))t`
`mL.=KA((T_(1)-T_(2))/(L))t`
`:.K-(mL.xxL)/(A(T_(1)-T_(2))XXT)`
`=(4.8xx3.36xx10^(5)xx0.1)/(0.36(100-0)xx3600)`
`=1.24" J/ms "^(@)C`


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