a stone of 1kg is thrown with a velocity of 20ms across the frozen sur

1.	a stone of 1kg is thrown with a velocity of 20ms across the frozen surface of a lake and comes to rest after travelling a distance of 50m what is the force of friction between the stone and the ice?
Answer» ONG>Explanation: m = 1kg u = 20m/s. v = 0m/s. s(DISTANCE travelled) = 50m using third equation of motion v²=u²+2as 0² = (20)²+2(a)(50) -400 = 100a a = -400/100 = -4m/s² (retardation) F = m×a F = 1×(-4) = -4N. (negative sign indicates the opposing force which is Friction) hope this helps

a stone of 1kg is thrown with a velocity of 20ms across the frozen surface of a lake and comes to rest after travelling a distance of 50m what is the force of friction between the stone and the ice?

Answer» ONG>Explanation:

m = 1kg

u = 20m/s. v = 0m/s.

s(DISTANCE travelled) = 50m

using third equation of motion

v²=u²+2as

0² = (20)²+2(a)(50)

-400 = 100a

a = -400/100 = -4m/s² (retardation)

F = m×a

F = 1×(-4) = -4N. (negative sign indicates the opposing force which is Friction)

hope this helps

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a stone of 1kg is thrown with a velocity of 20ms across the frozen surface of a lake and comes to rest after travelling a distance of 50m what is the force of friction between the stone and the ice?​

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a stone of 1kg is thrown with a velocity of 20ms across the frozen surface of a lake and comes to rest after travelling a distance of 50m what is the force of friction between the stone and the ice?