A stone of mass 2 kg is tied to a string of length 0.5 m. If the breaking tension of the string is 900 N, then the maximum angular velocity, the stone can have in uniform circular motion is

A stone of mass 2 kg is tied to a string of length 0.5 m. If the break

1.	A stone of mass 2 kg is tied to a string of length 0.5 m. If the breaking tension of the string is 900 N, then the maximum angular velocity, the stone can have in uniform circular motion is
Answer» `30rads^(-1)` `20 rad s^(-1)` `10rad s^(-1)` `40rad s^(-1)` SOLUTION :Here , Massof thestone`,m= 2kg ` Lengthof thestring` R= 0.5m` Breakingtension ` T = 900N` As `T= m r omega^2` ` thereforeomega^2 = (T) /(mr) = ( 900 )/(2 xx0.5 ) =900` ` oromega = 30 rad s^(-1)`