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A stone projected at angle `53^(@)` attains maximum height 25m during its motion in air. Then its distance from the point of projection where it will fall isA. 75mB. `400/3 m`C. `50 m`D. `60 m` |
Answer» Correct Answer - A velocity of projectile `=(50sqrt(5))/4 m//s` (by appling equation `v^(2)=u^(2)+2as` in vertical direction ) time of flight `=(8v)/(5g)` distance travelled `=v cos 53^(@) xxT=3/5 v xx8/5 v/g=75 m` (by putting the value of v ) |
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