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A stone thrown vertically upwards with initial velocity reaches a height 'h' before coming down.show that the time taken to go up is same as the time taken to come down. |
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Answer» v=U+at and s=ut+12at2 ∴s=(v−at)t+12at2=vt−at2+12at2 s=ut−12at2 As the STONE moves upward from A→B S = AB = H, t = t1, a= - g ( retardation ) u = u and v = 0 h = 0−12(−g)t21 h=12gt21 As the stone moves downward from B→A t=t2,u=0,s=h and . h=12gt22 From Eqs. (4) and (5) , t21=t22 t1=t2 |
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