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A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, the magnitude of acceleration is :A. `20 ms^(-2)`B. `12 m//s^(-2)`C. `9.9 ms^(-2)`D. `8 ms^(-2)` |
Answer» Correct Answer - C `omega=(14xx2pi)/25` `:.` magnitude of acceleration `=omega^(2)r=((14xx2pi)/25)^(2)xx80/100=9.9 m//s^(2)` |
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