A straight line cuts the x-axis at point A(1,0) and y-axis at point B, such that ∠OAB=α,(α>π/4). C is the middle point of AB. If B′ is the mirror image of B with respect to line OC and C′ is a mirror image of point C with respect to line BB′, then the ratio of the areas of triangle ABB′ and BB′C′ is

A straight line cuts the x-axis at point A(1,0) and y-axis at point B,

1.	A straight line cuts the x-axis at point A(1,0) and y-axis at point B, such that ∠OAB=α,(α>π/4). C is the middle point of AB. If B′ is the mirror image of B with respect to line OC and C′ is a mirror image of point C with respect to line BB′, then the ratio of the areas of triangle ABB′ and BB′C′ is
Answer» A straight line cuts the $x$ -axis at point $A (1, 0)$ and $y$ -axis at point $B$ , such that $∠ O A B = α, (α > π / 4)$ . $C$ is the middle point of $A B$ . If $B^{'}$ is the mirror image of $B$ with respect to line $O C$ and $C^{'}$ is a mirror image of point $C$ with respect to line $B B^{'}$ , then the ratio of the areas of triangle $A B B^{'}$ and $B B^{'} C^{'}$ is