A straight metal wire slides to the right at a constant 5 m/s along a

1.	A straight metal wire slides to the right at a constant 5 m/s along a pair of parallel metallic rails 25 cm apart. A 10 Ω resistor connects the rails on the left end. The entire setup lies wholly inside a uniform magnetic field of strength 0.5 T, directed into the page. Find the magnitude and direction of the induced current in the circuit.
Answer» Data : v = 5 m/s, l = 0.25 m, R = 10 Ω, B = 0.5T The induced current, i = \(\cfrac{e}R\) = \(\cfrac{Blv}R\) = \(\cfrac{(0.5)(0.25)(5)}{10}\) = 0.0625 A Since the magnetic flux into the page through the \| closed conducting loop increases, the induced current in the loop must be anticlockwise. Alternatively, Fleming’s right hand rule gives the direction of induced current in the moving wire from bottom to top.

A straight metal wire slides to the right at a constant 5 m/s along a pair of parallel metallic rails 25 cm apart. A 10 Ω resistor connects the rails on the left end. The entire setup lies wholly inside a uniform magnetic field of strength 0.5 T, directed into the page. Find the magnitude and direction of the induced current in the circuit.

Answer»

Data : v = 5 m/s, l = 0.25 m,

R = 10 Ω, B = 0.5T The induced current,

i = \(\cfrac{e}R\) = \(\cfrac{Blv}R\) = \(\cfrac{(0.5)(0.25)(5)}{10}\) = 0.0625 A

Since the magnetic flux into the page through the | closed conducting loop increases, the induced current in the loop must be anticlockwise. Alternatively, Fleming’s right hand rule gives the direction of induced current in the moving wire from bottom to top.

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