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A straight rod of length L has one of its end at the origin and the other at `X=L`. If the mass per unit length of the rod is given by `Ax` where A is constant, where is its centre of mass?A. `L/3`B. `L/2`C. `(2L)/(3)`D. `(3L)/4` |
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Answer» Correct Answer - C `X_(CM) = (intXdm)/(intdm) = (int_(0)^(L) (Ax).x.dx)/int_(0)^(L)(Ax).dx = (2L)/3` |
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