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A straight wire carring current I is turned into a circular loop. If the magnitude of magnetic moment associated with it in M.K.S. unit is M, the length of wire will beA. `(4pi)/(M)`B. `(Mpi)/(41)`C. `sqrt((4piM)/(1))`D. `sqrt((4piI)/(M))` |
Answer» Correct Answer - C M=IA `M=Ipir^(2)` `therefore r=sqrt((M)/(piI))` length of wire=`l=2pir` `l=2pisqrt((M)/(pil))` `=sqrt((M4pi^(2)))/(piI)` `sqrt((4piM)/(I))` |
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