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A straight wire having mass of 1.2 kg and length of 1m carries a current of 5 A. If the wire is suspended in mid-air by a uniform horizontal magnetic field, then the magnitude of field isA. 0.65TB. 1.53TC. 2.4TD. 3.2T

Answer» Correct Answer - C
For mid-air suspension the upward force F on wire due to magnetic field B must be balanced by the force due to gravity, then
`IlB=mg, B=(mg)/(Il)`
Here, `m=1.2kg, g = "10 m s"^(-2), I= 5A, l=1m`
`B=(1.2xx10)/(5xx1)=2.4T`


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