A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference of V esu. If e and m are charge and mass of the electron respectively, then the value of h//lamda (where lamda is the wavelength associated with the electron wave) is given by

A stream of electrons from a heated filament was passed between two ch

1.	A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference of V esu. If e and m are charge and mass of the electron respectively, then the value of h//lamda (where lamda is the wavelength associated with the electron wave) is given by
Answer» <html><body><p>`me V`<br/>`2 me V`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(me V)`<br/>`sqrt(2 meV)`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a> = (h)/(p) or (h)/(lamda) = p = <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>` <br/> `KE = (1)/(2)mv^(2)` so that `v = sqrt((2KE)/(m)) " But " KE = eV` <br/> `:. v = sqrt((<a href="https://interviewquestions.tuteehub.com/tag/2ev-1837250" style="font-weight:bold;" target="_blank" title="Click to know more about 2EV">2EV</a>)/(m)) :. (h)/(lamda) = mv = m sqrt((2eV)/(m)) = sqrt(2meV)`</body></html>