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A stream of water flowing horizontally with a speed of 15 m s^(-1)gushes out of a tube of cross-sectional area 10^(-2) m^2 , and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound ? |
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Answer» Solution :MASS of water hitting the wall per second ` = 10^3 kg m^(-3) xx 10^(-2) m^2 xx 15 ms^(-1) = 150 kg s^(-1)` FORCE by the wall = momentum loss of water per second ` =150 kg s^(-1) xx 15 ms^(-1) = 2.25 xx 10^3 N` |
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