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A stress of `10^(6) N//m^(2)` is required for breaking a material. If the density of the material is `3 xx 10^(3) Kg//m^(3)`, then what should be the minimum length of the wire made of the same material so that it breaks by its own weight `(g = 10m//s^(2))`A. 10 mB. 33.3 mC. 5 mD. 66.6 m |
Answer» Correct Answer - B (b) Maximum breaking stress `=(F)/(A)=(mg)/(A)` or `((Alrho)g)/(A)=sigma_("max")` `therefore l_("max")=(sigma_("max"))/(rhog)=(10^(6))/((3xx10^(3))(10))=33.33 m` |
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