A string 1 m long can just support a weight of 16 kg. A mass of 1 kg is attached to one of its ends. The body is revolved in a horizontal circle about the other fixed end of the stringy Find the greatest number of revolutions made by the mass per seconds ? (Take g=10 ms^(-2)) The maximum tension the string can withstand = weight of 16 kg.

A string 1 m long can just support a weight of 16 kg. A mass of 1 kg i

1.	A string 1 m long can just support a weight of 16 kg. A mass of 1 kg is attached to one of its ends. The body is revolved in a horizontal circle about the other fixed end of the stringy Find the greatest number of revolutions made by the mass per seconds ? (Take g=10 ms^(-2)) The maximum tension the string can withstand = weight of 16 kg.
Answer» SOLUTION :`MG = 16 xx 10 N = 160 N` Centripetal force `=F = mromega^(2) = MR (2pin)^(2)` `F = 160 N, m = 1kr, r = 1m, n=?` `n^(2) = F/(mr 4pi^(2)) = 160/(1 xx 1 xx 4pi^(2)) = 4`