1.

A string 1 m long can just support a weight of 16 kg. Amass of 1 kg is attached to one of its ends. The body is revolved in a horizontal circle about the other fixed end of the string. Find the greatest number of revolutions made by the mass per second ? (Take g = 10 ms^(-2))

Answer»


SOLUTION :`n^(2) = F//mr 4PI^(2) = 160//1 xx 1 xx 4pi = 4, n = 2 RPS`


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