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A string is hanging from a rigid support. A transverse pulse is excited at its free end. The speed at which the pulse travels a distance x is proportional toA. xB. `(1)/(x)`C. `(1)/(sqrt())`D. `sqrt(x)` |
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Answer» Correct Answer - D Speed of transverse pulse `v=sqrt((T)/(mu))` where `mu ` is mass of string per unit length. For a transverse pulse `T=mu xg` `therefore v=sqrt((mu xg)/(mu))or v prop sqrt(x)` |
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