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A string of length 20 cm and linear mass density 0.40 g//cm is fixed at both ends and is kept under a tension of 16 N . A wave pulse is produced at t = 0near an ends as shown in Fig. 7.17 (b) , which travels towards the other end . When will the string have the shape shown in the Fig . ( c). |
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Answer» SOLUTION :Given `mu = 0.40 g//CM = ( 0.40)/(1000) xx 100 = 0.040 kg//m` Wave speed in the stretched string , ` V = sqrt ((F)/(mu)) = sqrt((16)/( 0.040)) = 20 m//s` The string will have the same shape after the pulse TRAVELS a distance ` = 20 + 20 = 40 cm` THUS time period ` t = 0.40//20 = 0.02 s` |
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