1.

A student has to answer 6 out of 10 questions which are divided into two parts containing 5 questions each and he is permitted to attempt not more than 4 from any group. In how many ways can he make up his choice?

Answer»

The different possibilities are mentioned below;

Part I(5)Part II (5)Selection of 6
425C4 x 5C2 = 5C1 x 5C2
335C3 x 5C3
245C2 x 5C4 = 5C2 x 5C1

The required number of ways

= 5C1 × 5C2 + 5C3 × 5C3 + 5C2 × 5C1

= 5 × 10 + 10 × 10 + 10 × 5 = 200.



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