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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it ?A. A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.B. A screw gauge having 50 divisions in the circular scale and pitch as 1 mm.C. A meter scaleD. A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has `10` divisions in 1 cm. |
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Answer» Correct Answer - D Least count of varnier calliper is `0.01 cm` Hence it matches with the reading. |
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