A student measured the length of a rod and wrote it as 3.50 cm. Which

1.	A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?(A) A metre scale (B) A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm (C) A screw gauge having 100 divisions in the circular scale and pitch as 1 mm (D) A screw guage having 50 divisions in the circular scale and pitch as 1 mm
Answer» Answer is (B) A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm As per the question, the measured value is 3.50 cm. Hence the least count must be 0.01 cm = 0.1 mm For vernier scale, where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm 1 MSD = 1 mm and 9 MSD = 10 VSD, Least count = 1 MSD – 1 VSD = 0.1 mm Hence, correct option is (B).

A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?(A) A metre scale (B) A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm (C) A screw gauge having 100 divisions in the circular scale and pitch as 1 mm (D) A screw guage having 50 divisions in the circular scale and pitch as 1 mm

Answer»

Answer is (B) A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm

As per the question, the measured value is 3.50 cm. Hence the least count must be 0.01 cm = 0.1 mm

For vernier scale, where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm

1 MSD = 1 mm and 9 MSD = 10 VSD,

Least count = 1 MSD – 1 VSD = 0.1 mm

Hence, correct option is (B).

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