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A student says that he had applied a force F= - k√x on a particle and the particle moved in simple harmonic motion. He refuses to tell whether fe is a constant or not. Assume that he has worked only with positive x and no other force acted on the particle. (a) As x increases k increases. (b) As x increases k decreases. (c) As x increases k remains constant. (d) The motion cannot be simple harmonic. |
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Answer» (a) As x increases k increases. Explanation: Since the motion is simple harmonic, the force F=-⍵²x where ⍵² is a constant. Equating the force applied by the student we get, -k/x=-⍵²x →k=⍵²x² It is clear from this relation that if x increases k increases. |
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