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A student uses a simple pendulum of exactly 1 m length to determine g, the acceleration due to gravity. He uses a stop watch with the least count of 1 second for this and records 40 seconds for 20 oscillations. For this observation, which of the following statement(s) is (are) true?(a) Error ΔT in measuring T, the time period, is 0.05 seconds (b) Error ΔT in measuring T, the time period, is 1 second (c) Percentage error in the determination of g is 5% (d) Percentage error in the determination of g is 2.5% |
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Answer» Correct Answer is: (a, c) Error in measuring, T = 2s/40 = 0.05 s = ΔT T ∝ 1/√g Δg/g = 2ΔT/T = 1/20 Δg/g x 100% = 5%. |
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