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A substance used as a water softener has the following mass percentage composition : `42.07% Na, 18.9% P`, and `39.04%` of oxygen. Determine the empirical formula of the compound. `(Na = 23, P = 31, 0 = 16)` |
Answer» `{:("Element", "Moles", "Least ratio"),(Na, (42.07)/(23) = 1.829, (1.829)/(0.6) = 3),(P, (18.9)/(31) = 0.6, (0.6)/(0.6) = 1),(O, (39.04)/(16) = 2.44, (2.44)/(0.6) = 4):}` Empirical formula `= Na_(3) PO_(4)` |
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