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A sugar syrup of weight `214.2 g` contains `34.2 g` of sugar `(C_(12) H_(22) O_(11))`. Calculate a. the molal concentration. b. the mole fraction of the sugar in the syrup.A. 0.55B. 5.5C. 55D. 0.1. |
Answer» Correct Answer - A Water present = 214.2-342=180g Sugar =34.2 g `m=(W_(2) xx 1000)/(M_(2) xx W_(1)(g))=(34.2 xx 1000)/(342 xx 180)=0.55` |
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