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A suitable unit for gravitational constant isA. `kg-msec^(-1)`B. `Nm^(-1)sec`C. `Nm^2kg^(2)`D. `kgmsec^(-1)` |
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Answer» Correct Answer - C `F=(Gm_(1)m_(2))/(d^2)` `because` `G=(fd^2)/(m_1m_2)=(Nm^2)/(kg^2)` |
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