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A sulphate of a metal (A) on heating evolves two gases (B) and ( C) and an oxide (D). Gas (B) turns `K_(2)Cr_(2)O_(7)` paper green while gas ( C) forms a trimer in which there is no `S-S` bond. Compound (D) with HCl, forms a Lewis acid (E ) which exists as a dimer. Compounds (A), (B), ( C),(D) and (E) are respectively:A. `FeSO_(4),XO_(2),SO_(3),FeO_(3),FeCl_(3)`B. `Al_(2)(SO_(4))_(3),SO_(2),SO_(3),Al_(2)O_(3),FeCl_(3)`C. `FeS,SO_(2),SO_(3),FeSO_(4),FeCl_(3)`D. `FeS,SO_(2),SO_(3),Fe_(3)(PO_(4))_(2),FeCl_(2)`

Answer» Correct Answer - A


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