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A sulphuric acid solution has `pH = 3`. Its normality isA. `1//1000`B. `1//200`C. `1//2000`D. `1//100` |
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Answer» Correct Answer - A `pH = 3` `[H^(+)] = 1xx 10^(-3) mol//L` `H_(2)SP_(4) rarr 2H^(+) +SO_(4)^(2-)` `[H_(2)SO_(4)] = (1 xx 10^(-3))/(2) = (1)/(2000)M` `N = 2M` (for `H_(2)SO_(4))` Normality `= (2)/(2000) = (1)/(1000) N` |
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