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A swimmer crosses a flowing stream of width `d` to and fro normal to the flow of the river at time `t_(1)`. The time taken to cover the same distance up and down the stream is `t_(2)`. If `t_(3)` is the time the swimmer would take to swim a distance `2d` in still water, then relation between `t_(1),t_(2)`&`t_(3)`.A. `t_(1)^(2)=t_(2)t_(3)`B. `t_(2)^(2)=t_(1)t_(3)`C. `t_(3)^(2)=t_(1)t_(2)`D. `t_(3)=t_(1)+t_(2)` |
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Answer» Correct Answer - a Let v be the river velocity and u the velocity of swimmer in still water. Then `t_(1)=2(W/(sqrt(u^(2)-v^(2))))` `t_(2)=W/(u+v)+W/(u-v)=(2uW)/(u^(2)-v^(2)) and t_(3)=(2W)/u` Now we can see that `t_(1)^(2)=t_(2)t_(3)` |
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