1.

A swimmer wishes to cross a river 500m width flowing at a rate u. his speed w.r.t. still water is v. for this he makes an angle theta with the vertical as shown in the given figure then:

Answer»

to CROSS the river in minimum time `theta=0^(@)`
to cross the river in minumum time, `theta=30^(@)`
for u=3km/hr and v=5km/hr, the timetaken to cross the river in minimum time will be 6MIN.
for u=3 km/hr and v=5km/hr, the time taken to cross the river in minimum time will be 3MIN.

SOLUTION :`t=((d)/(ucos theta))` for minimum time `theta=0`.


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