A sysem is supplied power of 10 W. Temperature of the system becomes constant at 50^(@)C. With temperature of surrounding at 20^(@)C. When power is switched off system cools from t^(@)C to (t//m)^(@)C in one minute. The heat capacity of the system is 1200 J//^(@)C. find the limiting value of n.

A sysem is supplied power of 10 W. Temperature of the system becomes c

1.	A sysem is supplied power of 10 W. Temperature of the system becomes constant at 50^(@)C. With temperature of surrounding at 20^(@)C. When power is switched off system cools from t^(@)C to (t//m)^(@)C in one minute. The heat capacity of the system is 1200 J//^(@)C. find the limiting value of n.
Answer» <html><body><p>`n ge <a href="https://interviewquestions.tuteehub.com/tag/75-334971" style="font-weight:bold;" target="_blank" title="Click to know more about 75">75</a>`<br/>`n ge 55`<br/>`n ge 60`<br/>`n ge 100`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(dQ)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>) = K(50-20)=10, so K=1//3` <br/> Heat lost in 1 minute = `(dQ)/(dt)xx60(J)=Q` <br/> `(dQ)/(dt) = 1/3 (t-20)` <br/> Fall in temperature=`t//n` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = (Q)/(Delta theta) = ((1//3)xx(t-20)xx60)/((t//n))` <br/> <a href="https://interviewquestions.tuteehub.com/tag/putting-2963476" style="font-weight:bold;" target="_blank" title="Click to know more about PUTTING">PUTTING</a> values, `1200=20n=(400n)/(t)` <br/> Since `t gt 0` so `20n gt 1200` <br/> `n ge 60`.</body></html>