1.

A system absorbs 2 Kcals heat and does 500 J of work, then internal energy of the system will be …….

Answer»

6400 J
5400 J
7900 J
8900 J

Solution :System absorbs heat
`THEREFORE` dQ=+2000 cal =2000 x 4.2 J
=+8400 J
System does work,
`therefore DeltaW`=+500 J
From first law of thermodynamics,
`therefore DeltaW`=+500 J
dQ=dU+dW
`therefore` dU=dQ-dW
=8400-500
`therefore` dU=7900 J
It is POSITIVE so internal ENERGY INCREASES .


Discussion

No Comment Found